
Melbourne: Justine Henin continued her impressive comeback to grand slam action with a 7-6 1-6 6-3 win over fellow Belgian Yanina Wickmayer to reach the quarter-finals of the Australian Open on Sunday.
Henin, whose cool head during crunch moments has carried her to seven grand slam titles, saved three set points to force a tiebreaker before pouncing with three consecutive winners to seal the first set.
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Henin, who beat fellow Belgian Kim Clijsters for the 2004 title, stumbled in the second, but broke Wickmayer early in the third and sealed the match with an aggressive serve-volley.
Henin next meets Russian Nadia Petrova, who knocked out third seed and French Open champion Svetlana Kuznetsova in three sets.